6502 jsr instruction

 

 

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Why does the 6502 JSR instruction only increment the return address by 2 bytes (6502, design choices, retrocomputing)?. 3 Answers. 6502 Instructions in Detail bits 7 and 6 of operand are transfered to bit 7 and 6 of SR (N,V); the zero-flag is set to the result of operand AND accumulator. 6502 Instruction Encoding group mode opcode group mode opcode literal or address JSR $FDED pushes the program counter onto the stack then jumps to $FDED. Why does the 6502 JSR instruction only increment the return address by 2 bytes? Simply because the PC is already pushed before the second Information about the 6502 JSR Instruction JSR --- JSR stands for Jump to Subroutine JSR is one of the Subroutine Operations of 6502 instruction-set. Note on the MOS 6502: The JSR instruction affects no flags, causes the stack pointer to be decremented by 2 and substitutes new values into the programThe JSR instruction pushes the address of the last byte of the instruction. In this case, the address of the last byte is $C002 .

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